Your truck runs on 12V. You need to enter 12V.
That's 50 amps with efficiency losses.
Please let someone else do it so you don't set fire to your truck.

 

If you want to trust Google over actual advice from an automotive forum, from people with experience installing such systems , then go right ahead. But I don't know why you asked then. Not even auto insurance will help you, so at least have good life insurance.

 

Was originally looking for guidance on doing this task. Steps on what to do, not "what not to do"

 

you were given guidance and told exactly what to do, and your response was that you knew better. Good luck.

 

Sometimes there may be more than one way to get things done and still do it safely, but one wrong move is all it takes to do a lot of damage.

From that school of hard knocks, we learn some videos are not that accurate. Keep in mind anybody can put a video on the net whether it is right or not !

A good basic background of electricity is easy to obtain and will serve for a long time, something to consider.

 

Here is a simple mathematical equation you can use:

watts (in or out) = (Vin)*(Ain) = (Vout)*(Aout)

(Vin)*(Ain) = (Vout)*(Aout)

(Ain) = ((Vout)*(Aout)/(Vin))

(Ain) = ((120)*(4.25)/(12))

(Ain) = 42.5

where Ain equals Amps in
Aout equals Amps out
Vin equals Volts in
Vout equals Volts out

 

that makes more sense. Thank you for making it more understanding.

 

You are quite welcome!

Since nothing is 100% efficient, the Watts in will always be larger than the Watts out. By how much depends on multiple things such as the efficiency of the inverter, the ability of the inverter to dissipate the heat generated by it's components, the size of the wires carrying the current, the quality of the wires used to carry the current (are the wires pure copper or are they copper clad aluminum), how well the connectors used to terminate the wires are soldered or crimped, etc. Hence this is not a trivial endeavor.